Define the modulus of a complex number z and give the geometric interpretation of ∣z1−z2∣ for two complex numbers z1 and z2. On the basis of this interpretation establish the inequality ∣z1+z2∣⩽∣z1∣+∣z2∣.Use this result to prove, by induction, the corresponding inequality for ∣z1+⋯+zn∣.
The complex numbers a1,a2,…,an satisfy ∣ai∣⩽3 (i=1,2,…,n). Prove that the equation a1z+a2z2⋯+anzn=1 has no solution z with ∣z∣⩽1/4.