The non-collinear points A, B and C have position vectors a, b and c, respectively. The points P and Q have position vectors p and q, respectively, given by [[B]]p[[/B]]=λ[[B]]a[[/B]]+(1−λ)[[B]]b[[/B]] and [[B]]q[[/B]]=μ[[B]]a[[/B]]+(1−μ)[[B]]c[[/B]] where 0<λ<1 and μ>1. Draw a diagram showing A, B, C, P and Q.
Given that CQ×BP=AB×AC, find μ in terms of λ, and show that, for all values of λ, the the line PQ passes through the fixed point D, with position vector [[B]]d[[/B]] given by [[B]]d=−a+b+c[[/B]]. What can be said about the quadrilateral ABDC?