A uniform rod PQ of mass m and length 3a is freely hinged at P.
The rod is held horizontally and a particle of mass m is placed on top of the rod at a distance ℓ from P, where ℓ<2a. The coefficient of friction between the rod and the particle is μ.
The rod is then released. Show that, while the particle does not slip along the rod, (3a2+ℓ2)θ˙2=g(3a+2ℓ)sinθ, where θ is the angle through which the rod has turned, and the dot denotes the time derivative.
Hence, or otherwise, find an expression for θ¨ and show that the normal reaction of the rod on the particle is non-zero when θ is acute.
Show further that, when the particle is on the point of slipping, tanθ=2(ℓ2+aℓ+a2)μa(2a−ℓ).What happens at the moment the rod is released if, instead, ℓ>2a?