For an equation in sin(kx) or cos(kx) asked over an interval (how many solutions, the largest, or the sum), first transform the range of the inner argument (if 0≤x≤L then 0≤kx≤kL), solve the base equation across that widened interval, then map each value back by dividing by k. The widened interval is where you actually count.
Trigger: a multiple angle kx inside the trig function and a 'how many / largest / sum of solutions' question.
Instances:
(i) stretch 0≤x≤2π to 0≤2x≤4π (or 720∘) and list the 2x values before dividing;
(ii) stretch to 0≤3θ≤540∘ for a triple angle and count crossings of cos3θ=k;
(iii) intersect the kx-solutions of two conditions, keep the common ones, then halve;
(iv) for a wide outer interval, count how many full periods fit and add the partial-period solutions.