OCR (Cambridge University Press & Assessment) · United Kingdom
STEP 3 2016
2016
3h
13 questions worth 120 marks in total. Each part is annotated: check the hint if you are stuck, or reveal the worked solution once you have committed to an approach.
Let In=∫−∞∞(x2+2ax+b)n1dx, where a and b are constants with b>a2, and n is a positive integer.
By using the substitution x+a=b−a2tanu, or otherwise, show that I1=b−a2π.
Show that 2n(b−a2)In+1=(2n−1)In.
Hence prove by induction that In=22n−2(b−a2)n−21π(n−12n−2).
Integration
The distinct points P(ap2,2ap), Q(aq2,2aq) and R(ar2,2ar) lie on the parabola y2=4ax, where a>0. The points are such that the normal to the parabola at Q and the normal to the parabola at R both pass through P.
Show that q2+qp+2=0.
Show that QR passes through a certain point that is independent of the choice of P.
Let T be the point of intersection of OP and QR, where O is the coordinate origin. Show that T lies on a line that is independent of the choice of P.
Show further that the distance from the x-axis to T is less than 2a.
Coordinate Geometry & Conics
Given that ∫(x+1)2x3−2exdx=Q(x)P(x)ex+constant, where P(x)and Q(x) are polynomials, show that Q(x) has a factor of x+1.
Show also that the degree of P(x) is exactly one more than the degree of Q(x), and find P(x) in the case Q(x)=x+1.
Show that there are no polynomials P(x) and Q(x) such that ∫x+11exdx=Q(x)P(x)ex+constant. You need consider only the case when P(x) and Q(x) have no common factors.
Integration
By considering 1+xr1−1+xr+11 for ∣x∣=1, simplify r=1∑N(1+xr)(1+xr+1)xr. Show that, for ∣x∣<1, r=1∑∞(1+xr)(1+xr+1)xr=1−x2x.
Deduce that r=1∑∞sech(ry)sech((r+1)y)=2e−ycosech(2y) for y>0.
Hence simplify r=−∞∑∞sech(ry)sech((r+1)y), for y>0.
Sequences & Series
By considering the binomial expansion of (1+x)2m+1, prove that (m2m+1)<22m, for any positive integer m.
For any positive integers r and s with r<s, Pr,s is defined as follows: Pr,s is the product of all the prime numbers greater than r and less than or equal to s, if there are any such primes numbers; if there are no such primes numbers, then Pr,s=1.
For example, P3,7=35, P7,10=1 and P14,18=17.
Show that, for any positive integer m, Pm+1,2m+1 divides (m2m+1), and deduce that Pm+1,2m+1<22m.
Show that, if P1,k<4k for k=2, 3, …, 2m, then P1,2m+1<42m+1.
Prove that P1,n<4n for n⩾2.
Combinatorics & Binomial
Show, by finding R and γ, that Asinhx+Bcoshx can be written in the form Rcosh(x+γ) if B>A>0. Determine the corresponding forms in the other cases that arise, for A>0, according to the value of B.
Two curves have equations y=sechx and y=atanhx+b, where a>0.
In the case b>a, show that if the curves intersect then the x-coordinates of the points of intersection can be written in the form ±arcosh(b2−a21)−artanhba.
Find the corresponding result in the case a>b>0.
Find necessary and sufficient conditions on a and b for the curves to intersect at two distinct points.
Find necessary and sufficient conditions on a and b for the curves to touch and, given that they touch, express the y-coordinate of the point of contact in terms of a.
Trigonometry
Let ω=e2πi/n, where n is a positive integer. Show that, for any complex number z, (z−1)(z−ω)⋯(z−ωn−1)=zn−1.The points X0, X1, …, Xn−1 lie on a circle with centre O and radius 1, and are the vertices of a regular polygon.
The point P is equidistant from X0 and X1. Show that, if n is even, ∣PX0∣×∣PX1∣×⋯×∣PXn−1∣=∣OP∣n+1, where ∣PXk∣ denotes the distance from P to Xk.
Give the corresponding result when n is odd. (There are two cases to consider.)
Show that ∣X0X1∣×∣X0X2∣×⋯×∣X0Xn−1∣=n.
Complex Numbers
The function f satisfies, for all x, the equation f(x)+(1−x)f(−x)=x2. Show that f(−x)+(1+x)f(x)=x2. Hence find f(x) in terms of x. You should verify that your function satisfies the original equation.
The function K is defined, for x=1, by K(x)=x−1x+1. Show that, for x=1, K(K(x))=x.
The function g satisfies the equation g(x)+xg(x−1x+1)=x(x=1). Show that, for x=1, g(x)=x2+12x.
Find h(x), for x=0, x=1, given that h(x)+h(1−x1)=1−x−1−x1(x=0,x=1).
Functions & Curve Sketching
Three pegs P, Q and R are fixed on a smooth horizontal table in such a way that they form the vertices of an equilateral triangle of side 2a. A particle X of mass m lies on the table. It is attached to the pegs by three springs, PX, QX and RX, each of modulus of elasticity λ and natural length l, where l<32a. Initially the particle is in equilibrium. Show that the extension in each spring is 32a−l.
The particle is then pulled a small distance directly towards P and released. Show that the tension T in the spring RX is given by T=lλ(34a2+32ax+x2−l), where x is the displacement of X from its equilibrium position.
Show further that the particle performs approximate simple harmonic motion with period 2π3(4a−3l)λ4mla.
Mechanics
A smooth plane is inclined at an angle α to the horizontal. A particle P of mass m is attached to a fixed point A above the plane by a light inextensible string of length a. The particle rests in equilibrium on the plane, and the string makes an angle β with the plane.
The particle is given a horizontal impulse parallel to the plane so that it has an initial speed of u. Show that the particle will not immediately leave the plane if agcos(α+β)>u2tanβ.
Show further that a necessary condition for the particle to perform a complete circle whilst in contact with the plane is 6tanαtanβ<1.
Mechanics
A car of mass m travels along a straight horizontal road with its engine working at a constant rate P. The resistance to its motion is such that the acceleration of the car is zero when it is moving with speed 4U.
Given that the resistance is proportional to the car's speed, show that the distance X1 travelled by the car while it accelerates from speed U to speed 2U, is given by λX1=2ln59−1, where λ=P/(16mU3).
Given instead that the resistance is proportional to the square of the car's speed, show that the distance X2 travelled by the car while it accelerates from speed U to speed 2U is given by λX2=34ln89.
Given that 3.17<ln24<3.18 and 1.60<ln5<1.61, determine which is the larger of X1 and X2.
Mechanics
Let X be a random variable with mean μ and standard deviation σ. Chebyshev's inequality, which you may use without proof, is P(∣X−μ∣>kσ)⩽k21, where k is any positive number.
The probability of a biased coin landing heads up is 0.2. It is thrown 100n times, where n is an integer greater than 1. Let α be the probability that the coin lands heads up N times, where 16n⩽N⩽24n.
Use Chebyshev's inequality to show that α⩾1−n1.
Use Chebyshev's inequality to show that 1+n+2!n2+⋯+(2n)!n2n⩾(1−n1)en.
Probability & Statistics
Given a random variable X with mean μ and standard deviation σ, we define the kurtosis, κ, of X by κ=σ4E((X−μ)4)−3. Show that the random variable X−a, where a is a constant, has the same kurtosis as X.
Show by integration that a random variable which is Normally distributed with mean 0 has kurtosis 0.
Let Y1, Y2, …, Yn be n independent, identically distributed, random variables with mean 0, and let T=r=1∑nYr. Show that E(T4)=r=1∑nE(Yr4)+6r=1∑n−1s=r+1∑nE(Ys2)E(Yr2).
Let X1, X2, …, Xn be n independent, identically distributed, random variables each with kurtosis κ. Show that the kurtosis of their sum is nκ.