All vectors in this question lie in the same plane.
The vertices of the non-right-angled triangle ABC have position vectors a, b and c, respectively. The non-zero vectors u and v are perpendicular to BC and CA, respectively.
Write down the vector equation of the line through A perpendicular to BC, in terms of u, a and a parameter λ.
The line through A perpendicular to BC intersects the line through B perpendicular to CA at P. Find the position vector of P in terms of a, b, c and u.
Hence show that the line CP is perpendicular to the line AB.