5 (i) Given that a>b>c>0 are constants, and that x,y,z are non-negative variables, show thatax+by+cz≤a(x+y+z).In the acute-angled triangle ABC, a, b and c are the lengths of sides BC, CA and AB, respectively, with a>b>c. P is a point inside, or on the sides of, the triangle, and x, y and z are the perpendicular distances from P to BC, CA and AB, respectively. The area of the triangle is Δ.
(ii) (a) Find Δ in terms of a, b, c, x, y and z.
(b) Find both the minimum value of the sum of the perpendicular distances from P to the three sides of the triangle and the values of x, y and z which give this minimum sum, expressing your answers in terms of some or all of a, b, c and Δ.
(iii) (a) Show that, for all real a, b, c, x, y and z,(a2+b2+c2)(x2+y2+z2)=(bx−ay)2+(cy−bz)2+(az−cx)2+(ax+by+cz)2.(b) Find both the minimum value of the sum of the squares of the perpendicular distances from P to the three sides of the triangle and the values of x, y and z which give this minimum sum, expressing your answers in terms of some or all of a, b, c and Δ.
(iv) Find both the maximum value of the sum of the squares of the perpendicular distances from P to the three sides of the triangle and the values of x, y and z which give this maximum sum, expressing your answers in terms of some or all of a, b, c and Δ.